ArrayObject::__construct

(PHP 5, PHP 7)

ArrayObject::__construct — Construct a new array object

说明

public ArrayObject::__construct ([ mixed $input = array() [, int $flags = 0 [, string $iterator_class = "ArrayIterator" ]]] )

This constructs a new array object.

参数

input

The input parameter accepts an array or an Object.

flags

Flags to control the behaviour of the ArrayObject object. See ArrayObject::setFlags().

iterator_class

Specify the class that will be used for iteration of the ArrayObject object.

返回值

Returns an ArrayObject object on success.

错误／异常

Throws InvalidArgumentException when:

  • input is not an array or object
  • flags is not an integer
  • iterator_class is not an object that implements Iterator

范例

Example #1 ArrayObject::__construct() example

<?php
$array = array('1' => 'one',
               '2' => 'two',
               '3' => 'three');

$arrayobject = new ArrayObject($array);

var_dump($arrayobject);
?>

以上例程会输出：

object(ArrayObject)#1 (3) {
  [1]=>
  string(3) "one"
  [2]=>
  string(3) "two"
  [3]=>
  string(5) "three"
}

参见

User Contributed Notes

ashley at nospam dot zincdigital dot com 03-Jul-2009 03:18
The great confusion with this class is in its naming.  ArrayObject infers it will behave as an Array and as an Object.  It won't.  It behaves as an array.  It would better be called ArrayType.  You can, with some work, get it to work both as an object and as an array, but that is up to you.
german dot rumm at gmail dot com 14-Mar-2008 10:37
BTW, if you need to change array later, use exchangeArray() method. Good to know when you are writing a class that extends ArrayObject()

AFAIK, exchangeArray() doesn't return anything.

<?php
    $a = array('one', 'two', 'three');
    $ao = new ArrayObject($a);

    foreach ($ao as $element) {
        echo $element . ' '; // one two three
    }

    $b = array('four', 'five', 'six');
    $ao->exchangeArray($b); // returns null

    foreach ($ao as $element) {
        echo $element . ' '; // four five six
    }
?>
agalkin at agalkin dot ru 21-Aug-2007 01:56
Note that the first argument to ArrayObject::__construct, the initial array, is passed by reference. Nevertheless, modification of the array doesn't modify the object, so it may cause unexpected behaviour.

<?php
$array = array('foo' => 'initial');
$obj = new ArrayObject($array);

// array was passed by reference:
$obj['foo'] = 'modified';
var_dump($array); // foo => modified

// but it doesn't work backwards:
$array['foo'] = 'modified_again';
var_dump($obj); // foo => modified
var_dump($array); // foo => modified_again
?>
Grigori Kochanov 15-Jul-2006 03:51
As Marcus explained, the flag ArrayObject::SPL_ARRAY_AS_PROPS means the array element may be used as a property if there is no conflict with visible properties.

If there are visible properties in the class, the array element will not overwrite it's value.

<?php
class Rules extends ArrayObject {
    public $len = 1;
    function __construct($array){
        parent::__construct($array,ArrayObject::ARRAY_AS_PROPS);
        $this['len'] = 2;
    }
}
$x = new Rules(array(1,2));
echo $x->len;
?>
Result: 1

<?php
class Rules extends ArrayObject {
    private $len = 1;
    function __construct($array){
        parent::__construct($array,ArrayObject::ARRAY_AS_PROPS);
        $this['len'] = 2;
    }
}
$x = new Rules(array(1,2));
echo $x->len;
?>
Result: 2