DirectoryIterator::getType

(PHP 5, PHP 7)

DirectoryIterator::getType — Determine the type of the current DirectoryIterator item

说明

public DirectoryIterator::getType ( void ) : string

Determines which file type the current DirectoryIterator item belongs to. One of file, link, or dir.

参数

此函数没有参数。

返回值

Returns a string representing the type of the file. May be one of file, link, or dir.

范例

Example #1 DirectoryIterator::getType() example


<?php
$iterator = new DirectoryIterator(dirname(__FILE__));
foreach ($iterator as $fileinfo) {
    echo $fileinfo->getFilename() . " " . $fileinfo->getType() . "\n";
}
?>

以上例程的输出类似于：

. dir
.. dir
apple.jpg file
banana.jpg file
example.php file
pear.jpg file

参见

DirectoryIterator::isDir() - Determine if current DirectoryIterator item is a directory
DirectoryIterator::isDot() - Determine if current DirectoryIterator item is '.' or '..'
DirectoryIterator::isFile() - Determine if current DirectoryIterator item is a regular file
DirectoryIterator::isLink() - Determine if current DirectoryIterator item is a symbolic link

User Contributed Notes

boards at gmail dot com 09-Apr-2006 09:09


Note that this function returns the file type (e.g. "file", "dir", etc.) and not the MIME type.  To do that, you might want to use this:

<?php

for

(

  $dir = new DirectoryIterator('/some/directory');

  $dir->valid();

  $dir->next()

)

{

  $mime = mime_content_type($dir->getPathname());

}

?>