imagefilltoborder

(PHP 4, PHP 5, PHP 7)

imagefilltoborder区域填充到指定颜色的边界为止

说明

imagefilltoborder ( resource $image , int $x , int $y , int $border , int $color ) : bool

imagefilltoborder()xy(图像左上角为 0, 0)点开始用 color 颜色执行区域填充,直到碰到颜色为 border 的边界为止。【注:边界内的所有颜色都会被填充。如果指定的边界色和该点颜色相同,则没有填充。如果图像中没有该边界色,则整幅图像都会被填充。】

User Contributed Notes

admin at worldlanguages dot tk 10-Sep-2004 02:54
In the example below, for those with newer GD versions, it makes more sense to replace:

imagearc($im, $center, $center, $diametre, $diametre, 0, 360, $el_color);

with:

imageellipse($im, $center, $center, $diametre, $diametre, $el_color);

This is obviously simpler.
edrad at wanadoo dot fr 11-Jun-2003 05:02
Very useful to build a pseudo-sphere with a color gradient...

<?php
 $width
= 300;
 
$center = $width / 2;
 
$colordivs = 255 / $center;
 
$im = @imagecreate($width, $width);
 
$back_color = imagecolorallocate($im, 20, 30, 40);
 
imagefill($im, 0, 0, $back_color);
 for (
$i = 0; $i <= $center; $i++)
 {
    
$diametre = $width - 2 * $i;
   
$el_color = imagecolorallocate($im, $i * $colordivs, 0, 0);
   
imagearc($im, $center, $center, $diametre, $diametre, 0, 360, $el_color);
   
imagefilltoborder($im, $center, $center, $el_color, $el_color);
 }
 
imagepng($im);
?>

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