sqlite_num_rows

SQLiteResult::numRows

(PHP 5 < 5.4.0, PECL sqlite >= 1.0.0)

sqlite_num_rows -- SQLiteResult::numRows — Returns the number of rows in a buffered result set

说明

sqlite_num_rows ( resource $result ) : int

面向对象风格 (method):

SQLiteResult::numRows ( void ) : int

Returns the number of rows in the buffered result set.

参数

result: The SQLite result resource. This parameter is not required when using the object-oriented method.

Note:
此函数不能用于未缓冲的结果句柄。

返回值

Returns the number of rows, as an integer.

范例

Example #1 Procedural example


<?php
$db = sqlite_open('mysqlitedb');
$result = sqlite_query($db, "SELECT * FROM mytable WHERE name='John Doe'");
$rows = sqlite_num_rows($result);

echo "Number of rows: $rows";
?>

Example #2 Object-oriented example


<?php
$db = new SQLiteDatabase('mysqlitedb');
$result = $db->query("SELECT * FROM mytable WHERE name='John Doe'");
$rows = $result->numRows();

echo "Number of rows: $rows";
?>

参见

sqlite_changes() - Returns the number of rows that were changed by the most recent SQL statement
sqlite_query() - Executes a query against a given database and returns a result handle
sqlite_num_fields() - Returns the number of fields in a result set

User Contributed Notes

Dylan 28-Jun-2019 02:29


//I don't know about you. But for me this is what I had to do



$db = new SQLite3('databasename.db');

$result = $db->query("SELECT * FROM table_name");

$number_of_rows = 0;//for now



while($row = $result->fetchArray()) {

    $number_of_rows += 1;

}



echo "Number of rows: $number_of_rows";

be {a} t {dawt} pl 19-Oct-2015 08:43


@rezaamya



$db = new SQLite3('databasename.db');

$result = $db->query("SELECT * FROM users");

$rows = count ($result);

echo "Number of rows: $rows";



$rows value should always be 1 

... even if the query is invalid

I tested that on

SQLite Library 3.7.7.1

rezaamya at gmail dot com 17-Jun-2014 03:11


neither of "sqlite_num_rows($result)" and "$result->numRows()" is not working on SQLite3 !

you should use this way:



$db = new SQLite3('databasename.db');

$result = $db->query("SELECT * FROM users");

$rows = count ($result); 

echo "Number of rows: $rows";