SQLite3::prepare

(PHP 5 >= 5.3.0, PHP 7)

SQLite3::prepare — Prepares an SQL statement for execution

说明

public SQLite3::prepare ( string $query ) : SQLite3Stmt

Prepares an SQL statement for execution and returns an SQLite3Stmt object.

参数

query: The SQL query to prepare.

返回值

Returns an SQLite3Stmt object on success 或者在失败时返回 FALSE.

范例

Example #1 SQLite3::prepare() example


<?php
unlink('mysqlitedb.db');
$db = new SQLite3('mysqlitedb.db');

$db->exec('CREATE TABLE foo (id INTEGER, bar STRING)');
$db->exec("INSERT INTO foo (id, bar) VALUES (1, 'This is a test')");

$stmt = $db->prepare('SELECT bar FROM foo WHERE id=:id');
$stmt->bindValue(':id', 1, SQLITE3_INTEGER);

$result = $stmt->execute();
var_dump($result->fetchArray());
?>

参见

SQLite3Stmt::paramCount() - Returns the number of parameters within the prepared statement
SQLite3Stmt::bindValue() - Binds the value of a parameter to a statement variable
SQLite3Stmt::bindParam() - Binds a parameter to a statement variable

User Contributed Notes

Venkata Subbaraju 22-Jan-2016 12:27


Without checking the return value of "prepare" if "exec" is used then it will cause Fatal Error.



"PHP Fatal error:  Call to a member function execute() on a non-object "



To avoid this error,need to check return value as following:



<?php

 $db = new SQLite3('school.db');

 if($stmt = $db->prepare('SELECT id,student_name FROM classTen '))

 {

         $result = $stmt->execute();

         $names=array();

         while($arr=$result->fetchArray(SQLITE3_ASSOC))

         {

          $names[$arr['id']]=$arr['student_name'];

         }

}

?>